From: MuthuKumar (kmuthukumar@lycos.co.uk)
Date: Wed Oct 06 2004 - 23:30:59 EDT
> have a file that has records in it that are 133 characters in length. The
> actual data needed is only 54 characters the rest of the record is spaces.
> What I need to do is get the first 54 characters from each record. I need
> all 54 characters whether the are space or not. Any suggestions would be
> appreciated.
We can do this as,
sed:
sed "s/^\(.\{46\}\).*/\1/" filename
It will get the first 46 characters of every record on filename
awk:
awk '{ print substr($0,1,46) }' filename
cut:
while read line; do
echo $line | cut -c1,46
done < inputfile
Try any of the above.
HTH.
REgards
Muthukumar.
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