From: Abramson, Stuart (SAbramson@Wabtec.com)
Date: Fri Oct 24 2003 - 11:33:40 EDT
hpux-admins:
Question below.
Thanks to :
Mike Blanchette
Brent Cramer
Harry Pfeffer
Sabrina Lautier
Mitry Matyushkov
Sabrina suggested the simplest solution, below.
#!/usr/bin/ksh
for arg in $*; do
print $arg
done
Other suggest the use of "shift":
#!/usr/bin/ksh
echo "Number of parameters is " $#
while [ $# -gt 0 ]; do
echo $1
shift
done
Stuart Abramson | Off: 412/825-1434 | Cell: 412/417-1567 | email:
sabramson@wabtec.com
-----Original Message-----
From: Sabrina Lautier [mailto:slautier@amadeus.net]
Sent: Friday, October 24, 2003 11:19 AM
To: Abramson, Stuart
Subject: Re: [HPADM] Processing variable number of arguments in ksh
scripts:
This should do the work:
#!/usr/bin/ksh
for arg in $*; do
print $arg
done
Rgds
Sabrina Lautier
Amadeus SAS
DEV-IIS-OAU-SYS
+33 (0)4 97 23 09 56
slautier@amadeus.net
From: "Abramson, Stuart" <SAbramson@Wabtec.com>@DutchWorks.nl on
24/10/2003 11:09 AST
Sent by: hpux-admin-owner@DutchWorks.nl
To: "Hpux-Admin (E-mail)"
<hpux-admin@dutchworks.nl>
cc:
Subjec [HPADM] Processing variable number
t: of arguments in ksh scripts:
hpux-admins:
I want to process a variable number of arguments to a ksh script one at a
time:
ksh script.ksh arg1 agr2 ... argN
where:
##
# script.ksh
#
for each argument
do
symdev -sid -XXX -sa 03b write_disable $ARGX
-noprompt
done
where $ARGX is each argument 1 to N one at a time.
How does one do that?
I don't know how many there will be at each call. There must be one
minimum.
I think you do this with "shift", somehow....
Stuart
Stuart Abramson | Off: 412/825-1434 | Cell: 412/417-1567 | email:
sabramson@wabtec.com
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