From: Thad Schultz (tschul@woodward.com)
Date: Thu Nov 21 2002 - 09:27:34 EST
I got my script to work.
I realize that the $ in my original regex is suppose to anchor to the end of
the line but I thought that awk would treat the end of the first column as
the end of the line since I was matching my regex against $1 and I figured
awk new nothing about entire lines. I guess my thinking was wrong. I
changed the $ in my regex to a tab character and now it works like I wanted
it to:
RESULT=$(awk -v PART="$PART[\|\t]" '$1~PART {print $2}' $PN_LIST)
Thad Schultz
EDA Librarian / Sys Admin
Woodward Industrial Controls
tschul@woodward.com
ph (970)498-3570
fax (970)498-3077
www.woodward.com
-----------------------------------
Original Question:
I have a script that matches a part number the user enters
against a file with two tab separated columns. Column 1
contains a part number and column 2 contains a revision
letter. The part number can look like 1751-896 or
1751-923|ext. I want to match what is entered up to the
first "|" or the end of the column. If they enter a partial
number (1751-9) I do not want a match. I've tried the
following script and it finds numbers that have a "|" in
them. It does not find numbers without the "|" in them.
What am I doing wrong or what are other ways to do what I'm
trying to do?
#!/usr/bin/ksh
PN_LIST=pn_list.txt
printf "Enter part number for search: "
read PART
RESULT=$(awk -v PART="$PART[\|\$]" '$1~PART {print $2}' $PN_LIST)
.
<processing of $RESULT>
.
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