From: Jef Lee (jef.lee@ITVISION.COM.AU)
Date: Tue Jan 13 2004 - 04:35:38 EST
This does it:
ls -1 | sort -n -t"." -k 3.5,3.8 -k 3.1,3.4
Jef...
-----Original Message-----
From: IBM AIX Discussion List [mailto:aix-l@Princeton.EDU] On Behalf Of
David Antrobus
Sent: Tuesday, January 13, 2004 4:24 PM
To: aix-l@Princeton.EDU
Subject: Re: Sorting Question
What it sounds like to me is you want to sort by date.
Would a basic "ls -ltr" work?
_______________________________
David Antrobus
AIX Systems Administrator
Caudwell Distribution Group
-----Original Message-----
From: Mills, John T [mailto:John.T.Mills@ERAC.COM]
Sent: 12 January 2004 21:29
To: aix-l@Princeton.EDU
Subject: Re: Sorting Question
Yes I looked at that first. The output is not correct.
sort -nr does a sort from left to right, sorting
12302003
12292003
...
01102004
What I really need to do is sort on the last 4, then on the first 4
characters. Unfortunately "filename" varies in length.
Any thoughts?
Thanks,
John
-----Original Message-----
From: IBM AIX Discussion List [mailto:aix-l@Princeton.EDU]On Behalf Of
John Jolet
Sent: Monday, January 12, 2004 2:07 PM
To: aix-l@Princeton.EDU
Subject: Re: [aix-l] Sorting Question
sort -nr.
On Mon, 2004-01-12 at 13:56, Mills, John T wrote:
> Give an output of 'ls -1 .':
>
> filename.image.01102004
> filename.image.12252003
> filename.image.12262003
> filename.image.12272003
> filename.image.12282003
> filename.image.12292003
> filename.image.12302003
>
> How could I use sort or/and awk to sort the list like this?
>
> filename.image.12252003
> filename.image.12262003
> filename.image.12272003
> filename.image.12282003
> filename.image.12292003
> filename.image.12302003
> filename.image.01102004
>
> Thanks,
>
> John T. Mills
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