format of a drive: swapon vs. disklabel

From: Cohen, Andy (Andy.Cohen@cognex.com)
Date: Wed Jun 12 2002 - 17:15:07 EDT


Hi,

If I issue:

        disklabel -r dsk4

I get:

8 partitions:
# size offset fstype fsize bsize cpg # ~Cyl values
  a: 281250 0 AdvFS # 0 -
124*
  b: 2804687 281250 swap # 124*-
1365*
  c: 8380080 0 unused 0 0 # 0 -
3707
  d: 2623488 532480 unused 0 0 # 235*-
1396*
  e: 2623488 3155968 unused 0 0 # 1396*-
2557*
  f: 2600624 5779456 unused 0 0 # 2557*-
3707
  g: 2580823 3097655 AdvFS # 1370*-
2512*
  h: 2700678 5679402 unused 0 0 # 2513*-
3707

partition b has an fstype of 'swap'.

However, if I issue:

        swapon -s

I get:

Swap partition /dev/disk/dsk0b (default swap):
    Allocated space: 175292 pages (1.34GB)
    In-use space: 1 pages ( 0%)
    Free space: 175291 pages ( 99%)

Swap partition /dev/disk/dsk2b:
    Allocated space: 125000 pages (976MB)
    In-use space: 1 pages ( 0%)
    Free space: 124999 pages ( 99%)

Total swap allocation:
    Allocated space: 300292 pages (2.29GB)
    Reserved space: 59680 pages ( 19%)
    In-use space: 2 pages ( 0%)
    Available space: 240612 pages ( 80%)

which only shows dsk0b and dsk2b as being used for swap.

I presume it's ok then go reuse dsk4b for something else. i.e., - does the
output of 'swapon' display more accurately what is being used than a
'disklabel -r'?

Thanks alot!
Andy

===================================================
Andy Cohen
Database Systems Administrator
COGNEX Corporation
(508) 650-3079 Fax: (508) 650-3337
andy.cohen@cognex.com www.cognex.com
cell: (617) 470-0034
===================================================



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