From: Hickey, Michael (HickeyM@bsci.com)
Date: Wed Apr 23 2003 - 07:54:50 EDT
The overwhelming majority submitted the following:
awk '$3>=15{print $3}'
Thanks to all those who responded.
Regards,
Mike
> -----Original Message-----
> From: Hickey, Michael
> Sent: Tuesday, April 22, 2003 11:05 AM
> To: Sun Managers Mailing List (E-mail)
> Subject: Awk script help
>
> Can someone push me in the right direction of the proper syntax to take a
> file,
> dr.out containing multiple rows and 3 fields as below, and print only the
> lines that
> have a number >= 15 in field 3?
>
> 04/12/03 20:56 15.3
> 04/12/03 21:56 15.3
> 04/12/03 22:56 15.3
> 04/12/03 23:57 18.5
>
> Thanks in advance.
>
> Mike
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