From: Polak, Jon (Jon_Polak@icgcomm.com)
Date: Thu Oct 23 2003 - 18:01:58 EDT
Thanks to all for the very prompt replies.
(and also to everyone who was kind enough to inform me of their vacation
status)
Once again, thinking out-of-the-box solved the issue. A very simple change
allows one script to do all the processing as in this version sent by Mr.
Schmidt.
###########
#!/bin/ksh
report_func () {
LOGFILE=$1
grep -i "my data" $LOGFILE| awk '{ ----long awk script here----}'
}
for FIL in `find /usr/xyz -name "file00*" -mtime +30 {} \;`
do
report_func $FIL
done
###########
The only issue I see with this would be if the filenames had embedded
whitespace, which in my case they don't.
Finally, As I was writing this summary, another method was suggested by Mr.
Caines, simplified as follows. I will try this method too.
find ... | xargs my_function
Original post below:
to the ksh wizards...
I want to consolodate two ksh scripts into one but in this case I am not
sure if it is possible.
Any suggestions would be greatly appreciated.
The first script is the main one that does a find command to invoke the
second script on each matching entry.
###########
#!/bin/ksh
# this is script1.ksh
find /usr/xyz -name "file00*" -mtime +30 -exec script2.ksh {} \;
###########
#!/bin/ksh
# this is script2.ksh
LOGFILE=$1
grep -i "my data" $LOGFILE | awk '{ --------- long awk script here
---------}'
###########
Optimally I would like to define script2 as a function within the script1 as
in the following example.
###########
#!/bin/ksh
report_func () {
LOGFILE=$1
grep -i "my data" $LOGFILE| awk '{ --------- long awk script here
---------}'
}
find /usr/xyz -name "file00*" -mtime +30 -exec report_func {} \;
###########
Unfortunately the exec portion of the find command doesn't seem to have
visibility to the function, even if I export the function. Has anyone ever
found a way to script something like this using just one ksh script?
Thanks
Jon
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