From: Bill Weiss (houdini+pen-test@clanspum.net)
Date: Mon Apr 24 2006 - 00:56:26 EDT
Paul Sebastian Ziegler(psz@observed.de)@Sat, Apr 22, 2006 at 10:30:43AM +0200:
> Hallo list!
>
> I've been on this for quite some time and after failing to find out
> anything on the Internet I've finally decided to propose this question
> here. Any help would be greatly appreciated!
>
> Due to interest I have started to try to understand
> buffer-overflow-attacks. The theory is fine with me. But now I'm getting
> quite some trouble when trying to write exploiting scripts.
>
> Let me show you what I mean:
(code and example runs cut)
Using your C code and the same python code:
(%:~/tmp)- ./a.out `python -c "print 'A' * 524"`
AAAAAAA (lots of As cut)
a.out: stack smashing attack in function main()
zsh: abort ./a.out `python -c "print 'A' * 524"`
(%:~/tmp)- python
Python 2.4.2 (#1, Oct 16 2005, 00:06:10)
[GCC 3.3.6 (Gentoo Hardened 3.3.6, ssp-3.3.6-1.0, pie-8.7.8)] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> import os
>>> os.system("./a.out " + ("A" * 524))
AAAAAAA (again, lots of As)
a.out: stack smashing attack in function main()
6
>>>
(%:~/tmp)- python vuln.py
AAAAAAA (As galore)
a.out: stack smashing attack in function main()
(%:~/tmp)
Gentoo with kernel 2.6.12-gentoo-r10, GCC 3.3.6 (Gentoo Hardened 3.3.6,
ssp-3.3.6-1.0, pie-8.7.8), Python 2.4.2 built with this GCC.
The Hardened stuff is why I'm seeing "stack smashing attack", but I can't
imagine why this would be causing a failure where yours isn't (while
running from within python).
Unless the newer kernels added something here (which I doubt), it should
be working for you. We're on almost the same build.
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