From: Fyodor (fygrave@gmail.com)
Date: Mon Aug 13 2007 - 05:36:44 EDT
the code might do some manipulation with the data in %i0 after the
first, and before the second return, i.e. before you hit the segfault.
you can disassemble the routine and see if you can alter the execution
flow by supplying different values, which would be restored into
registers after the first return. Usually there's alot of stuff to
play around at this point. In some cases you can can control the
memory addresses where routine would write stuff, so you can also
trigger the code execution by overwriting, for example some pointers
in the GOT table.
On 8/13/07, heigick <heigick@gmail.com> wrote:
> Hi all,
>
> I'm currently attempting privilege escalation on a compromised client
> Solaris 7 machine. Not being very fluent with the SPARC ABI, I'm starting
> with the basics, for example the POC code there:
> http://seclists.org/bugtraq/1999/Mar/0004.html
> (the machine in question has noexec_user_stack set)
>
> However, even the basic exploit for 'hole' dumps core -- using the (almost ;-) exact
> same code and looking at the register state gives the following for i and l :
>
> l0 0xdeadbe10
> l1 0xdeadbe11
> l2 0xdeadbe12
> l3 0xdeadbe13
> l4 0xdeadbe14
> l5 0xdeadbe15
> l6 0xdeadbe16
> l7 0xdeadbe17
>
> i0 0xff2b6b54
> i1 0xdeadbe11
> i2 0xdeadbe12
> i3 0xdeadbe13
> i4 0xdeadbe14
> i5 0xdeadbe15
>
> which seems totally OK, except for %i0, which is not the value I
> expected: I always get the same address (0xff2bb6b54), regardless of
> the address written into the input buffer. As this is supposed to be
> the pointer fed to system(), this is not a good thing.
>
> Any ideas on why this value is overwritten when every other register seems fine ?
>
> Thanks
>
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