From: jmiller (secadmin@subversive.cc)
Date: Wed Jul 31 2002 - 02:54:14 EDT
<snip>
> > The following example should bypass the "x=1" statement and print the
> > original value of "x" which is 0 (zero). Here's the code.
> >
> > -=-=-=-=-=-=-=-=-=-=-=-=-=
> > void function(int a, int b, int c) {
> > char buffer1[5];
> > char buffer2[10];
> > int *ret;
> >
> > ret = buffer1 + 12;
> > (*ret) += 8;
> > }
i am failing to see how this should bypass anything,
it is all byval, not byref. this function is isolated from your prog.
bufffer1, buffer2, and ret are all dissapearing when the function is done...
i am also failing to see how the function would affect x at all.
JMiller
> >
> > void main() {
> > int x;
> >
> > x=0;
> > function(1,2,3);
> > x=1;
> > printf("%d\n",x);
> > }
> > -=-=-=-=-=-=-=-=-=-=-=-=
> >
> > When I compile and execute this code it displays one and exits. I have
tryed
> > this on RedHat 7.3 and Debian 2.2r6, both giving me the same result.
Does
> > anyone have any insight into why this wouldn't work? After looking into
the
> > assembly behind it, I think it has something to do with the "word size",
but
> > can't seem to find any information as to what the "word size" is in
Debian
> > or RedHat.
> >
> > Any and All comments/suggestions are more than welcome. Also if anyone
knows
> > of some other good text files/documents that talk about buffer overflows
I
> > would be happy to receive links.
> >
> > Leonard Leblanc
> >
> >
> >
>
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