From: Grimes, Niall (Niall.Grimes@intecbilling.com)
Date: Mon Aug 22 2005 - 06:48:20 EDT
Thanks to all who replied.
David Lodge, David Lee Totsch and Bill Hassell hit the nail on the head -
'ls' doesn't understand extended regular expressions but uses globbing to
pattern match. So the following command line does the trick for me:
ls /path/to/@(first|second)/directory
Of course, I should have gone to 'man sh-posix' first.
Bill also noted that:
the shell only pattern matches with ordinary regular expressions and
ls/ll doesn't know anything at all about regular expressions.
What ls processes is exactly what the shell passes. To see this, put
echo in front, something like this:
echo ls /etc/i*
I'll keep that tip handy!
Thanks also to the following:
David R Antoch
Eef Hartman
Mark D Schupsky
Jeff Lightner
Shyam Hazari
Blazej Antczak
Vidal Cazarez
Ruby Domalanta
Brett Geer
C Beerse
> ______________________________________________
> From: Grimes, Niall
> Sent: 19 August 2005 14:47
> To: hpux-admin@DutchWorks.nl
> Subject: Listing explicit directories using regular expressions
>
> Hi admins,
>
> Is it possible to list the contents of multiple explicit directories?
> For example, with the following directory structure:
>
> /path/to/first/directory
> /path/to/second/directory
> /path/to/third/directory
> /path/to/fourth/directory
> /path/to/fifth/directory
>
> ...is it possible to list the contents of the ../first/.. and
> ../second/.. directories with a single 'ls' command line?
>
> I've tried the following but it doesn't work:
>
> # ls /path/to/[first|second]/directory
>
>
> Thanks.
>
>
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