From: Holger.VanKoll@SWISSCOM.COM
Date: Tue Mar 02 2004 - 15:20:06 EST
you need \\. , dont you?
(1)root@sbe15342 581# echo asdf.asdf\\nasdfasdf
asdf.asdf
asdfasdf
(0)root@sbe15342 582# echo asdf.asdf\\nasdfasdf|grep .
asdf.asdf
asdfasdf
(0)root@sbe15342 583# echo asdf.asdf\\nasdfasdf|grep \.
asdf.asdf
asdfasdf
(0)root@sbe15342 584# echo asdf.asdf\\nasdfasdf|grep \\.
asdf.asdf
(0)root@sbe15342 585#
-----Original Message-----
From: IBM AIX Discussion List [mailto:aix-l@Princeton.EDU] On Behalf Of
Bill Verzal
Sent: Tuesday, March 02, 2004 9:10 PM
To: aix-l@Princeton.EDU
Subject: Re: Grep Question
With regex, a "." means "any character". Use "\." to find literal "."
characters.
BV
--------------------------------------------------------
"If everything is coming your way, then you are in the wrong lane"
Bill Verzal
AIX Administrator, Komatsu America
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"Kumar, Praveen
(cahoot)"
<Praveen.Kumar@CA
To
HOOT.COM> aix-l@Princeton.EDU
Sent by: IBM AIX
cc
Discussion List
<aix-l@Princeton.
Subject
EDU> Grep Question
03/02/2004 01:33
PM
Please respond to
IBM AIX
Discussion List
<aix-l@Princeton.
EDU>
Hi *,
I want to search for a string (82.44.203.222.82681071601925321)
from
a file. i have around 150 similar number , so i am using a script to do
this...my script does not create file even after redirecting...can some
let
me know where am i failing.
i think when i am doing grep it takes .(dot) in the literal meaning.
TIA
Praveen
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