From: Robert Bardos (Robert.Bardos@ZUGERKB.CH)
Date: Mon Jul 15 2002 - 10:40:16 EDT
Hi Drew,
maybe like this? Using the tr command?
var1=0%
var2=`echo $var1 | tr -d "%"`
echo $var1 $var2
The result is: 0% 0
HTH
Robert
> -----Ursprüngliche Nachricht-----
> Von: Drew [SMTP:apt@dcs-success.com]
> Gesendet am: Montag, 15. Juli 2002 13:57
> An: aix-l@Princeton.EDU
> Betreff: Script variable assignment issue
>
> Hi fello AIXers,
> I am writing a script that includes the line:
>
> grep loss tempfile | cut -f7 -d" "
>
> The above line returns returns a one or two digit number with a percent
> sign. Usually it returns only: 0%
>
> What I'm trying to do is, remove the % sign and initialize this value to a
> variable, which I can then perform
> basic functions on. Any help would be greatly appreciated.
>
> I was trying something like:
> VALUE=[grep loss tempfile | cut -f7 -d" "]
>
> but it isn't working. I think I need to extract the 0 from the % and then
> assign it a variable name. I'm just not sure
>
> Thanks all,
>
> Drew
>
>
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